an interpretation
A muon enters Earth space at 7 o'clock and ends life at 8 (for clarity duration exaggerated) as the observatory registers. Because it is travelling at high speed some effective mass is added on its journey. By the principle of least action it is clear that near mass time runs faster, because a photon passing mass seeks a path with as big steps (oscillations of lower frequencies) as possible and a minimum of these. Ref.: Vasily Yanchilin, The Quantum Theory of Gravitation. Observed is a route not close to the mass but at a distance where time runs slower and the tempo of oscillations is reduced. So on the clock of the descending muon one and a half hour pass. With its continuing high speed then a bigger distance is bridged than its brother in the laboratorium performs. (?)
In volume III Physics, edition 2009 to me available, by Giancoli in 36-5 a mistake occurs. In the spaceship the physical processes pass faster, but light is according to Yanchilin related to the potential of the total mass of the universe (which is in all directions the same, a scalar) (New interpretation of the special theory of relativity). Photons going from the bottom to the top of the spacevehicle and back thus behave in agreement not with the movement of the spaceship but harmonious with that universal potential, which is augmentend a little bit by contribution of Earth. Things are just the other way than written by the author. A on Earth sees the photon departing from the bottom of the spaceship only and B sees it when it has returned from the mirror. The kosmonaut (Yanchilin is from Russia) notes a distance from the location above A to the mirror plus one to B; a horizontal and a vertical component are involved.
Redraw the upper picture on page 965.
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